2v^2+4v+6=2

Solution for 2v^2+4v+6=2 equation:

Simplifying
2v2 + 4v + 6 = 2

Reorder the terms:
6 + 4v + 2v2 = 2

Solving
6 + 4v + 2v2 = 2

Solving for variable 'v'.

Reorder the terms:
6 + -2 + 4v + 2v2 = 2 + -2

Combine like terms: 6 + -2 = 4
4 + 4v + 2v2 = 2 + -2

Combine like terms: 2 + -2 = 0
4 + 4v + 2v2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + 2v + v2) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(2 + 2v + v2)' equal to zero and attempt to solve:

Simplifying
2 + 2v + v2 = 0

Solving
2 + 2v + v2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + 2v + -2 + v2 = 0 + -2

Reorder the terms:
2 + -2 + 2v + v2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2v + v2 = 0 + -2
2v + v2 = 0 + -2

Combine like terms: 0 + -2 = -2
2v + v2 = -2

The v term is 2v.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2v + 1 + v2 = -2 + 1

Reorder the terms:
1 + 2v + v2 = -2 + 1

Combine like terms: -2 + 1 = -1
1 + 2v + v2 = -1

Factor a perfect square on the left side:
(v + 1)(v + 1) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.